Question

What are the solutions for x to the equation (x-3)(x+8)=0

Answer 1

For this case we have a factored expression, of a second degree equation:

(
`(x-3) (x + 8) = 0`

To find the solutions:

• 
  `x-3 = 0`

we add 3 to both sides of the equation:

`x=3`

• 
  `x+8=0`

We subtract 8 on both sides of the equation:

`x = -8`

Thus, the solutions of the equation are:

`x_ {1} = 3\\x_ {2} = - 8`

Answer:

`x_ {1} = 3\\x_ {2} = - 8`