Question

A compound has the percent composition 47.40% Pd, 28.50% O, 21.40% C, and 2.69% H. Based on this information, which molecular formulas could represent the compound?

PdO2C2H3
Pd(O2CCH3)2
Pd(O2C2H3)3
PdO4C2H9
Pd2C8H12O8

Answer 1

Pd(O₂CCH₃)₂

Explanation

Answer 2

Pd(O2CCH3)2

Pd2C8H12O8

Step-by-step explanation:

Given:

% Pd = 47.40

% O = 28.50

% C = 21.40

% H = 2.69

To determine:

Molecular formula of the compound containing Pd, O, C and H

Calculation:

Let the mass of the compound = 100g

Therefore based on the % compositions:

Mass of Pd = 47.40g

Mass of O = 28.50g

Mass of C = 21.40g

Mass of H = 2.69g

Atomic mass of Pd = 106.42 g/mol

Atomic mass of O = 15.99 g/mol

Atomic mass of C = 12.01 g/mol

Atomic mass of H = 1.00 g/mol

`moles\ of\ Pd = (47.40g)/(106.42g/mol) =0.4454`

`moles\ of\ O = (28.50g)/(15.99g/mol) =1.782`

`moles\ of\ C = (21.40g)/(12.01g/mol) =1.782`

`moles\ of\ H= (2.69g)/(1.00g/mol) =2.690`

Ratio:

`Pd = (0.4454)/(0.4454) = 1.00\\\\O = (1.782)/(0.4454) = 4.00\\\\C = (1.782)/(0.4454) = 4.00\\\\H = (2.690)/(0.4454) = 6.039`

The empirical formula is : PdO4C4H6

Molecular formula = n(Empirical formula)

If n = 1

Molecular formula = PdO4C4H6 i.e. Pd(O2CCH3)2

If n= 2

Molecular formula = 2(PdO4C4H6)= Pd2O8C8H12