Answer:
The correct answer is option B.
Explanation:
The given rational expression is:
![(x^2-4)/(x^2+5x+6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ptzejpx5136zzy98rlsxy3airautio6il8.png)
Factor the numerator and the denominator:
![(x^2-2^2)/(x^2+2x+3x+6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rnxrbcqbu985pt3qvevw0ilmgkcgb2ilx7.png)
Factor the numerator using difference of two squares and the denominator using factorization by grouping.
![((x-2))/(x(x+2)+3(x+2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6pycppia4012d2r7ywxr2od28skpykdop6.png)
![((x-2)(x+2))/((x+2)(x+3))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k4ojbemjtt4b9w1me2npi30mpywle59a5k.png)
This function is defined if and only if the denominator is not zero.
That is: (x+3)(x+2)≠0.
x≠-2,x≠-3
We simplify now to obtain:
![(x-2)/(x+3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hfekl0kjb9ne9ex130qaf69pz4rqxyot4f.png)
The correct choice is the second option.