Question

Factor the expression below by grouping. 3x-6+xy-2y.

A. (x-2)(3+y)
B.(x+2)(3-y)
C.2(x-2(xy-2y)
D.(3x-6)(Cyrus-2y)

Answer 1

A: (x-2)(3+y)

3x - 6 + xy - 2y

(3x - 6) + (xy - 2y)

3(x - 2) + y(x - 2)

Your two terms are: (3 + y) and (x - 2)

Answer 2

Answer: The correct option is (A).
`(x-2)(3+y).`

Step-by-step explanation: We are given to factor the following expression by grouping :

`E=3x-6+xy-2y~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)`

Since we are given to factorize the expression (i) by grouping, so we will take 3 common from first two terms and y common from last two terms.

The factorization of expression (i) is as follows :

`E\\\\=3x-6+xy-2y\\\\=3(x-2)+y(x-2)\\\\=(x-2)(3+y).`

Thus, the required factored form of the given expression is
`(x-2)(3+y).`

Option (A) is CORRECT.