Answer:
x=-3 ; x= 4
Explanation:
zeros of the function are the value of x at which the function becomes zero. Or graphically when the graph line crosses the x-axis those values of x are the zeros of the function.
Finding zeros of given function f(x)= x^2-x-12/ x^2+x-12 by substituting f(x)=0
0= x^2-x-12/ x^2+x-12
0= (x+3)(x-4)/(x-3)(x+4)
(x+3)(x-4)=0
(x+3)=0 ; (x-4)=0
x=-3 ; x= 4
the zeros of the function f(x)= x^2-x-12/ x^2+x-12 are at point x=-3 and x= 4 !