Question

How many grams of NaHCO3 would you need to react with 6 moles of H2SO4?

The balanced chemical equation is:
H2SO4(aq) + 2 NaHCO3 (s) —-> Na2SO4 (aq) + 2 CO2 (g) + 2 H2O

Answer 1

`\boxed{\text{1000 g}}`

Step-by-step explanation:

We know we will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.

M_r: 84.01

H₂SO4 + 2NaHCO₃ ⟶ Na₂SO₄ + 2CO₂ + 2H₂O

n/mol: 6

1. Use the molar ratio of NaHCO₃ to calculate the moles of NaHCO₃.

`\text{Moles of NaHCO$_(3)$ = 6 mol H$_(2)$SO$_(4)$} * \frac{\text{2 mol NaHCO$_(3)$}}{\text{1 mol H$_(2)$SO$_(4)$}}\\=\text{12 mol NaHCO$_(3)$}`

2. Use the molar mass of NaHCO₃ to calculate the mass of NaHCO₃.

`\text{Mass of NaHCO$_(3)$ = 12 mol NaHCO$_(3)$} * \frac{\text{84.01 g NaHCO$_(3)$}}{\text{1 mol NaHCO$_(3)$}}\\\\= \text{1000 g NaHCO$_(3)$}`

You must use
`\boxed{\textbf{1000 g}}` of NaHCO₃.