Question

A gas at pressure 4.4 atm and 32.14 L has a new volume of 72 L, what is the new pressure

Answer 1

`\boxed{\text{2.0 atm}}`

Step-by-step explanation:

If the temperature is constant, the only variables are pressure and volume, so we can use Boyle’s Law.

p₁V₁ = p₂V₂

Data:

p₁ = 4.4 atm; V₁ = 32.14 L

p₂ = ?; V₂ = 72 L

Calculation:

4.4 × 32.14 = p₂ × 72

141 = 72p₂

`p_(2) = (141)/(72) = \textbf{2.0 atm}`

The new pressure is
`\boxed{\textbf{2.0 atm}}`