well lets see here
Part 1:
the full rotation will have a perimeter of 1
so we can then determine the distance from the big gear how much the smaller gear will move
smaller gear=the disance of: 1* (22/7)*2*2
If the distance converted into degrees, then:
gear A rotation= gear A distance/ gear A perimeter * 360°
gear A rotation= (22/7) * 2 *2/ {(22/7) * 8 *8} * 360°
gear A rotation= (1/16) * 360°= 22.5 degrees
Part 2:
The problem is similar to part 1 but the number is reversed.
bigger gear= 1 * (22/7) * 8 *8
bigger gear= (22/7) * 8 *8/ {(22/7) * 2 *2} = 16 rotation
hope i could help u