Answer:
1) Second option:
![y=0.25x+2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ocp6ty2jw5wm99vpqe3ib6r2ip4tqvn5cv.png)
2) Third option: $14,500
Explanation:
1) The equation of the line in Slope-intercept form is:
![y=mx+b](https://img.qammunity.org/2020/formulas/mathematics/high-school/8nudzfk4b5l0arb9iixag2w8am6zn99zlr.png)
Where m is the slope and b is the y-intercept.
You know the point (20,7) of the line and you can observe in the graph that the y-intercept is:
![b=2](https://img.qammunity.org/2020/formulas/mathematics/high-school/bjv4xugivleowsouvi50ktorjjsc14v627.png)
Then, you can substitute these values into the equation
![y=mx+b](https://img.qammunity.org/2020/formulas/mathematics/high-school/8nudzfk4b5l0arb9iixag2w8am6zn99zlr.png)
and solve for the slope "m":
![7=m(20)+2\\\\7-2=20m\\\\m=(5)/(20)\\\\m=0.25](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tkhltr0rnj32rviilttuzbk5gqgpqkkxfk.png)
Therefore, the equation of this line is:
![y=0.25x+2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ocp6ty2jw5wm99vpqe3ib6r2ip4tqvn5cv.png)
2) To calculate the total cost of producing 50 engines, you need to substitute
into the equation of the line
. Then you get:
![y=0.25(50)+2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cjie284phdawa3ba9q0hct8udm27bnwfo5.png)
![y=0.25x+2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ocp6ty2jw5wm99vpqe3ib6r2ip4tqvn5cv.png)
![y=14.5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/op6zb7st3dpfrv88ubzkwmhrq97h4k9cyd.png)
Since the y-axis represents the total cost "y" in thousands of dollar, then the total cost of producing 50 engines is:
$14,500