Question

Pls help!!!

The volume of a triangular pyramid is 1800 cubic inches. If the base of the solid has a height of 18 inches and a base of 12 inches, what is the height of the pyramid?

Answer 1

The height of the pyramid is
`50\ in`

Explanation:

we know that

The volume of a triangular pyramid is equal to

`V=(1)/(3)BH`

where

B is the area of the base

H is the height of the pyramid

we have

`V=1,800\ in^(3)`

The area of the base B is equal to

`B=(1)/(2)(12)(18)=108\ in^(2)`

substitute and solve for H

`1,800=(1)/(3)(108)H`

`5,400=(108)H`

`H=5,400/(108)=50\ in`