Answer:
10 pairs of earrings and 5 necklaces (the maximum profit will be $250)
Explanation:
Let x be the number of earrings and y be the number of necklaces Lisa makes.
1. Lisa only has enough materials to make 15 total jewelry items per week, then
![x+y\le 15.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bp2ur63meat6zd0eoh7bxwq0q0s5t0tf0x.png)
2. It takes half an hour to make a pair of earrings, so it takes her
hours to make x earrings. It takes her 1 hour to make a necklace, so it takes her y hours to make y necklaces. Lisa only has 10 hours a week to make jewelry, thus
![(x)/(2)+y\le 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/iy4zzlg4azdctk6kvqejqu4nut0zn2adnk.png)
3. Lisa makes a profit of $15 on each pair of earrings and $20 on each necklace. In total her profit is
![P=15x+20y.](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wj3d9ugpfngoosnc8mbbv0s9ggr2gv9lfu.png)
You have to find the maximum value of the function
with respect to inequalities
![x+y\le 15\\ \\(x)/(2)+y\le 10](https://img.qammunity.org/2020/formulas/mathematics/middle-school/j0hdd287qg3ezfac3vsuq54wepgtxewuaq.png)
Draw the solution set on the coordinate plane (see attached diagram). The maximum value of the efunction P is at point (10,5) and is
![P=15\cdot 10+20\cdot 5=150+100=\$250](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6ffixg9ijnqo5uy1cazqckwi2j8s0sinhh.png)