75.9k views
5 votes
Select the functions that have a value of 0.

sin270
cos90
tan0
csc(-180)
cos(-90)
cot270

User Beckley
by
5.3k points

2 Answers

6 votes

Answer:

cos90° = 0°, tan0° = 0°,cos(-90°) = 0°, cot270° = 0°

Explanation:

User Hector Sanchez
by
5.7k points
6 votes

Answer:

cos90° = 0°, tan0° = 0°,

cos(-90°) = 0°, cot270° = 0°

Explanation:


k\in\mathbb{Z}\\\\\sin x=0\iff x=180^ok\\\\\cos x=0\iff x=90^o+180^ok\\\\\tan x=0\iff x=180^ok\\\\\cot x=0\iff x=90^o+180^ok\\\\\csc x\\eq0\ \text{for}\ x\in\mathbb{R}-\{180^ok\}\\========================\\\\\sin270^o\\eq0\\\\\cos90^o=\cos(90^o+180^o\cdot0)=0\\\\\tan0^o=\tan(180^o\cdot0)=0\\\\\csc(-180^o)\\eq0\\\\\cos(-90^o)=\cos(90^o-180^o)=\cos(90^o+180^o\cdot(-1))=0\\\\\cot270^o=\cot(90^o+180^o)=0

User Brent Mannering
by
4.7k points