Question

Identify whether each process is either oxidation or reduction:

Al → Al3+ + 3 e-
S2- → S + 2 e-
Cu → Cu2+ + 2 e-

Show ALL work.

Answer 1

Al → Al³⁺ + 3 e⁻, is an oxidation process.

S²⁻ → S + 2 e⁻, is an oxidation process.

Cu → Cu²⁺ + 2 e⁻, is an oxidation process.

Step-by-step explanation:

• The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).

• The oxidation process is the process in which electrons are lost and produce positively charged ions.

• The reduction process is the process in which electrons is gained and negatively charge ions are produced.

So,

• Al → Al³⁺ + 3 e⁻, is an oxidation process.

Al loses 3 electrons and produce Al³⁺c

• S²⁻ → S + 2 e⁻, is an oxidation process.

S²⁻ loses 2 electrons and produce S.

• Cu → Cu²⁺ + 2 e⁻, is an oxidation process.

Cu loses 2 electrons and produce Cu²⁺.