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What is the mass of 4.56 moles of copper (ii) fluoride​

User Tiberiu
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1 Answer

3 votes

Answer:

463.0 g.

Step-by-step explanation:

  • We can use the following relation:

n = mass/molar mass.

where, n is the mass of copper(ii) fluoride​ (m = 4.56 mol),

mass of copper(ii) fluoride​ = ??? g.

molar mass of copper(ii) fluoride​ = 101.543 g/mol.

∴ mass of copper(ii) fluoride​ = (n)(molar mass) = (4.56 mol)(101.543 g/mol) = 463.0 g.

User Hongbo
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