2 Answers

Brent Rittenhouse · Answer 1 · 2020-09-13T12:41:27+0000

For this case we have that by definition:

$Sin (90) = 1\\Cos (90) = 0$

Now, the tangent of 90 is given by:

$tg (90) = \frac {Sin (90)} {Cos {90}} = \frac {1} {0}$

Thus, it is observed that the tangent of 90 degrees is not defined. Is obtained ∞.

Similarly:

$Sin (-90) = - 1\\Cos (-90) = 0$

Now, the tangent of -90 is given by:

$tg (-90) = \frac {Sin (-90)} {Cos {-90}} = \frac {-1} {0}$

Thus, it is observed that the tangent of -90 degrees is not defined.

Answer:

False

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