Question

asked Feb 22, 2020 148k views

2 Answers

Alex Choroshin · Answer 1 · 2020-02-25T03:27:18+0000

Answer:

x_1=4.158

x_2=0.8416

Explanation:

For an equation of the form
ax^2 +bx +c

The quadratic formula is

$(-b\±√(b^2 -4ac))/(2a)$

In this case the equation is:

2x^2 - 10x + 7 = 0

Then

$a= 2\\b= -10\\c= 7$

Therefore, using the quadratic formula we have:

$x=(-(-10)\±√((-10)^2 -4(2(7)))/(2(2))$

$x=(5\±√(11))/(2)$

x_1=4.158

x_2=0.8416

Lanoxx · Answer 2 · 2020-02-28T22:39:00+0000

ANSWER

$x = ( 5 )/(2) - \frac{\sqrt {11} } {2} \: or \: x = ( 5 )/(2) + \frac{\sqrt {11} } {2}$

EXPLANATION

The given quadratic equation is:

$2{x}^(2) - 10x + 7 = 0$

Comparing this equation to

$a{x}^(2) + bx + c = 0$

we have

a=2, b=-10 and c=7.

The solution is given by the quadratic formula;

$x = \frac{ - b \pm \sqrt{ {b}^(2) - 4ac } }{2a}$

We plug in the values to get,

$x = \frac{ - - 10 \pm \sqrt{ {( - 10)}^(2) - 4(2)(7) } }{2(2)}$

This implies that

$x = \frac{ 10 \pm \sqrt{ {100} - 56 } }{4}$

$x = \frac{ 10 \pm \sqrt {44 } }{4}$

$x = \frac{ 10 \pm 2\sqrt {11 } }{4}$

$x = \frac{ 5 \pm \sqrt {11 } }{2}$

$x = ( 5 )/(2) - \frac{\sqrt {11} } {2} \: or \: x = ( 5 )/(2) + \frac{\sqrt {11} } {2}$

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