Answer:
![\large\boxed{A=(223.3+49\pi)m^2}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pw6yyw6ykv46h8v3pb3m9xm8v6sbf16jz9.png)
Explanation:
(look at the picture)
We have:
two halves of circle (whole circle) with radius r = 7m;
the suqare wih length side a = 14m;
the triangle with base b = 14m and hight h = 3.9m.
The formula of an area of a circle:
![A_1=\pi r^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/y2oyd4y6rj5rxrtw02j7ym722w4caqzxlj.png)
Substitute:
![A_1=\pi(7^2)=49\pi\ m^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9jyx861w1kett7x22zp1pm651kenr6jpl2.png)
The formula of an area of a square:
![A_2=a^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/nl21gv9u9w801xqxowptqdnpupvlele1qi.png)
Substitute:
![A_2=14^2=196\ m^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ovf3e6mbiha4rvj5kad4zq3t6jcmd5bnse.png)
The formula of an area of a triangle:
![A_3=(bh)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/docnh78j6seffvvnwl6kq3rbuwuh4tikxj.png)
Substitute:
![A_3=((14)(3.9))/(2)=(7)(3.9)=27.3\ m^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yluzputgms37sqeoh8qxv1cmvscrdm53j9.png)
The area of a figure:
![A=A_1+A_2+A_3\\\\A=49\pi+196+27.3=223.3+49\pi](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tncobm3nszsnayhow9kiz890w6f1adctmf.png)