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An unknown substance with a mass of 25 grams releases 550 joules of energy when undergoing a temperature increase of 10 degrees Celsius. What is the specific heat of that substance? Show your work in the space below.

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Answer:

2.2 J/°C.g.

Step-by-step explanation:

  • To solve this problem, we can use the relation:

Q = m.c.ΔT,

where, Q is the amount of heat released by the unknown substance (Q = 550 J).

m is the mass of the unknown mass (m = 25.0 g).

c is the specific heat of the unknown substance (c = ??? J/°C.g).

ΔT is the difference between the initial and final temperature (ΔT = 10°C).

∴ c = Q/(m.ΔT) = (550 J)/(25.0 g)(10°C) = 2.2 J/°C.g.

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