Answer:
19958400
10
8
1814400
Explanation:
* Lets explain how to solve the problem
- Permutation is the act of arranging the members into order
- The number of permutations of n members taken r at a time is
denoted by nPr
- nPr = n!/(n - r)! , where n! means n(n - 1)(n - 2)(n - 3) ......... × 1
* Lets solve the problem
- There are eleven people on a softball team
∴ n = 11
- There are nine different positions
∴ r = 9
∴ The number of ways can be made = 11P9
∵ 11P9 = 11!/(11 - 9)! = 11!/2! = 19958400
* The number of total arrangements of the player is 19958400
- If Amy does not want to play pitcher
∵ They are 11 players
∴ The number of players can be pitch = 11 - 1 = 10
* If Amy does not want to play pitcher, then there are now 10 people
available to pitch
- Assuming the pitcher has already be chosen
∴ There are 10 remaining players
∵ The positions are 9
∴ The remaining positions = 9 - 1 = 8
* There are 8 remaining positions
- Lets find how many ways to arrange the remaining positions
∵ n = 10
∵ r = 8
∴ 10P8 = 10!/(10 - 8)! = 10!/2! = 1814400
* The number of ways to arrange the remaining players is 1814400