2 Answers

Hobbs · Answer 1 · 2020-11-17T00:29:57+0000

Answer:

The correct application of the quadratic formula is:

$x=(9\pm √((-9)^2-4(6)(22)))/(2(6))$

The quadratic equation is given by:

y=6x^2-9x+22

We know that the solution of the quadratic equation:

y=ax^2+bx+c

is given by:

$y=(-b\pm √(b^2-4ac))/(2a)$

Here we have:

a=6

b=-9

and

c=22

Hence, the quadratic formula is given by:

$x=(-(-9)\pm √((-9)^2-4\cdot (6)\cdot (22)))/(2\cdot (6))$

i.e.

$x=(9\pm √((-9)^2-4(6)(22)))/(2(6))$