Question

Help me answer this question please

Answer 1

`{f}^( - 1) =\pm √(x + 1)`

Step-by-step explanation

The given function is

`f(x) = {x}^(2) - 1`

Let

`y = {x}^(2) - 1`

Interchange x and y to get:

`x= {y}^(2) - 1`

Solve for y,

`x + 1 = {y}^(2)`

Take square root of both sides to get,

`\pm √(x + 1) = y`

This is the same as:

`y = \pm √(x + 1)`

Therefore the inverse is

`{f}^( - 1) =\pm √(x + 1)`