Question

point p is located at (x, y). The point is reflected in the y-axis. Point P’s image is located at (__?__)

Answer 1

P'(-x,y)

Explanation:

The question is asking you to reflect over the y-axis. You pick a random point in the first quadrant and reflect that point over the y-axis. The point will land in the second quadrant and the x-value will have been negated (changed sign).

Ex.

(5,4) would become (-5,4)

P(x,y) reflected over the y-axis P'(-x,y)

Answer 2

-x,y?

Explanation:

if it's being reflected across the y-axis then that should go in to the negative side of the graph and the same if its being reflected across the x-axis, in which case it would be x,-y