9514 1404 393
Answer:
(min, max) are exact or rounded to thousandths, so you can round as may be required
5. (10.607, 14.229)
6. (-1.586, -0.764)
7. (4, 5.211)
8. (-3.5, -2.342)
Explanation:
Given:
the attached function definitions and intervals
Find:
the minimum and maximum on the given interval
Solution:
In a couple of cases, the coefficient of x is negative, indicating the basic square root function has been reflected over the y-axis. That will put the maximum at the left end of the interval, instead of the right end, where it would otherwise be.
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5. minimum: f(3.5) = 5√(3.5+1) +1 = 5√4.5 +1 = 10.607
maximum: f(6) = 5√(6+1) +1 = 5√7 +1 = 14.229
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6. minimum = f(-2) = √(-(-2)) -3 = √2 -3 = -1.586
maximum = f(-5) = √(-(-5)) -3 = √5 -3 = -0.764
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7. minimum = f(-6) = 2√(3 -(-6)) -2 = 2√9 -2 = 4
maximum = f(-10) = 2√(3 -(-10)) -2 = 2√13 -2 = 5.211
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8. minimum = f(0) = (1/2)√(0 +1) -4 = -3.5
maximum = f(10) = (1/2)√(10+1) -4 = (1/2)√11 -4 = -2.342