Question

A field with an area of 2880 ft^2 has the shape of a rectangle, whose length is 12 ft larger than its width. Find the dimensions of this field.

Answer 1

w=48,l=60

Step-by-step explanation

Let the width of the field be, w , then,

the length of the field will be:

`l = 12 + w`

The area of a rectangle is

`Area = lw`

This implies that:

`w(12 + w) = 2880`

Expand

`{w}^(2) + 12w = 2880`

`{w}^(2) + 12w - 2880 = 0`

`(x + 60)(x - 48) = 0`

This implies that,

`w = - 60 \: w = 48`

The dimensions are positive, the width is 48 and the length is 12+48=60