Question

the vector [ 5,1] represent the velocity of an ultralight plane what is the direction of this vector to the nearest degree​

Answer 1

`011\degree`

Explanation:

The direction of a vector is given by;

`\theta=\tan^(-1)((y)/(x))`

The given vector is <5,1>.

The x-component of this vector is 5 and the y-component is 1.

We substitute the values into the formula to obtain;

`\theta=\tan^(-1)((1)/(5))`

We use our scientific calculator to obtain;

`\theta=11.3099`

Therefore the direction of the given angle is
`011\degree` to the nearest degree.