Question

How many grams of phosphorus are in 500.0 grams of calcium phosphide? (i need the work also)

Answer 1

`\boxed{\text{170.0 g P}}`

Step-by-step explanation:

The formula of calcium nitride is Ca₃P₂.

The masses of each element are:

`\begin{array}{lrcr}\text{3Ca:} & 3 * 40.08&=& \text{120.24 u}\\\text{2P:} & 2* 30.97&=& \text{61.94 u}\\& \text{TOTAL} & = & \text{182.18 u}\\\end{array}`

So, there are 61.94 g of P in 182.18 g of Ca₃P₂.

In 500 g of Ca₃P₂:

`\text{Mass of P} = \text{500.0 g Ca$_(3)$P$_(2)$} * \frac{\text{61.94 g P}}{\text{182.18 g Ca$_(3)$P$_(2)$}} = \text{170.0 g P}`

There are
`\boxed{\textbf{170.0 g P}}` in 500.0 g of Ca₃P₂.