Answer:
Yes, because the sum of all of the probabilities is 1.
Explanation:
The given probability equation is:
, where x belongs to {1,2,3,4}.
![P(1)=(2(1)-1)/(16)=(1)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v6lx4rk4ok0c61n1xpd1pqmku6gcwrz6rl.png)
![P(2)=(2(2)-1)/(16)=(3)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8x7y2ltlr1lne5g9j9nycj4musmxdmr2uq.png)
![P(3)=(2(3)-1)/(16)=(5)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rbp4z6ztmf1kfojc0nz32cvmxp3rp74kax.png)
![P(4)=(2(4)-1)/(16)=(7)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gzjwlo67slp4rcxm3ru4magdtrysookv1g.png)
Let us sum all the probabilities to obtain;
![P(1)+P(2)+P(3)+P(4)=(1)/(16)+ (3)/(16)+(5)/(16)+(7)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/x6o4459uqmnbfoxytbqvsnh6j1agv6qmv1.png)
![P(1)+P(2)+P(3)+P(4)=(1+3+5+7)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v68x90lqoeykmxe6dzepbt74mctqwa39ei.png)
![P(1)+P(2)+P(3)+P(4)=(16)/(16)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5rs542bw3zzo9h7rl5qw6hgvdje9h9udh8.png)
![P(1)+P(2)+P(3)+P(4)=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a1lc32qjm42vd3n1hzgvhoyf1y68gklbcu.png)
Since the sum of all the probabilities is 1, it is a probability distribution