Question

Can anyone help with this please

Answer 1

For this case we have a function of the form
`y = f (x)`, where:

`f (x) = \frac {5 + x} {6 + 3x}`

We must evaluate the function at
`x = a-1`

So:

`g (a-1) = \frac {5+ (a-1)} {6 + 3 (a-1)}\\g (a-1) = \frac {5 + a-1} {6 + 3a-3}\\g (a-1) = \frac {4 + a} {3 + 3a}`

Thus, the value of the function is:

`\frac {4 + a} {3 + 3a}`

Answer:

`g (a-1) = \frac {4 + a} {3 + 3a}`