Question

Which of the following values are zeros for the functions below? Select all that apply. g(x)=(x62+4x-12)(x-3)

Answer 1

Too Confusing !!

but I think it's

g(x)=(x^2+4x-12)(x-3)

=(x+6)(x-2)(x-3)

=x+6 = 0

-6 -6

x=-6

x-2 = 0

+2 +2

x=2

x-3 = 0

+3 +3

x=3

The zeros are {-6, 2, 3}

hope this helps ! :)