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Find the value of x, rounded to the nearest tenth

Find the value of x, rounded to the nearest tenth-example-1
User Arnekolja
by
8.4k points

2 Answers

7 votes

Answer:

B

Explanation:

Use the law of sines to create a proportion.


(18)/(sin(90))=(x)/(sin(20))

Solve for
x.


x=6.2

User Phoet
by
8.1k points
4 votes

Answer:


x=6.2

Explanation:

Given triangle is right triangle so we can use trigonometric ratios to find the value of x.


\sin\left(\theta\right)=(opposite)/(hypotenuse)


\sin\left(20^o\right)=(x)/(18)


\sin\left(20^o\right)(18)=x


(0.34202014332566873304409961468226)(18)=x


6.1563625798620371947937930642807=x


x=6.1563625798620371947937930642807


x=6.2

Hence final answer is
x=6.2

User Aidenhjj
by
8.9k points

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