Answer:
![2y√(2x)](https://img.qammunity.org/2022/formulas/mathematics/college/8lhz4xgyl7el2mmropv06r7wthreumwslg.png)
Explanation:
For this we have to divide like normally but for the exponents we will subtract them since this is a division problem. We would've added them if we were multiplying.
![(√(32x^5y^8))/(√(4x^4y^6))=√(8xy^2)](https://img.qammunity.org/2022/formulas/mathematics/college/rz3voocguboc0es2p4is0maqweewnm422v.png)
Now we will split the 8 into 4 and 2. Also we can take the square root of y² while we're at it.
![y√(4)√(2x)](https://img.qammunity.org/2022/formulas/mathematics/college/z29r3tdtdetbmcogd1f5azl0uuzlz5v0q1.png)
Now we take the square root of 4.
![2y√(2x)](https://img.qammunity.org/2022/formulas/mathematics/college/8lhz4xgyl7el2mmropv06r7wthreumwslg.png)