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What is the solution of this system of linear equations? 3y=3/2x+6 1/2y-1/4x=3.

User Jasko
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2 Answers

2 votes

Answer:

Third: no solution

Explanation:

User Brad Wood
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1 vote

Answer:

No solution

Explanation:

Please, separate equations with a comma, or the word "and," or a semicolon.

Next, determine the LCD and multiply both equations by it, so as to elimiinate the fractional coefficients.

3y=3/2x+6 1/2y-1/4x=3

should be written as the system

3y=(3/2)x+6 Use parentheses around the fraction for clarity

(1/2)y-(1/4)x=3 Same: use parentheses

The LCDs here are 2 (for the first equation) and 4 (for the second equation). Multiply the first equation by 2 to eliminate the fractions:

3y=(3/2)x+6 → 6y = 3x + 12, and

4[ (1/2)y-(1/4)x=3 ] → 2y - x = 12

Let's use the substitution method to solve this system. Solve the 2nd equation for x, obtaining x = 2y - 12. Substitute 2y - 12 for x in the 1st equation 6y = 3x + 12:

6y = 3(2y - 12) + 12, or

6y = 6y - 36 + 12

This reduces to 0 = -24, which is never true. Thus,

this system has NO solution.

User Prakash Murthy
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