Answer:
a)
![a_n = 50 (0.52) ^ {n-1}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/puy4u1prctabqvtuiw5e08ho107c5z7s7k.png)
b)
![a_6 = 50 (0.52) ^ 5 = 1.90\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9m3cbf3fd2fb7sy87hpvfqkw8e0kcmmjfb.png)
Explanation:
If each curved path has 52% of the previous height this means that
![(a_(n+1))/(a_n) = 0.52](https://img.qammunity.org/2020/formulas/mathematics/middle-school/63gqewjrtbumbcqf1ty6h64xqf1nj5h080.png)
Then the radius of convergence is 0.52 and this is a geometric series.
The geometric series have the form:
![a_n = a_1 (r) ^ {n-1}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uged1e1zpk4q3f5iw2l23k6tu7y7f3hbzh.png)
Where
is the first term of the series and r is the radius of convergence.
In this problem
meters = 50 cm
![r = 0.52](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7g9xonkbjw0cl6p6g9fix04btoaztds0ad.png)
a) Then the rule for the sequence is:
![a_n = 50 (0.52) ^ {n-1}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/puy4u1prctabqvtuiw5e08ho107c5z7s7k.png)
b) we must calculate
![a_6 = 50 (0.52) ^ 6-1\\\\a_6 = 50 (0.52) ^ 5 = 1.90\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dswb7gbpx5bezk4awxt1asb8hesrn5klvz.png)