Question

Which equation shows how to calculate how many grams (g) of Mg(OH)2 would be produced from 4mol KOH? The balanced reaction is:

MgCl2(small 2) + 2KOH -----> Mg(OH)2(small2) + 2KCL

Answer 1

4 mol of KOH would produce 116.6 g of Mg(OH)₂

Step-by-step explanation:

According to the following balanced equation:

• MgCl₂+ 2 KOH -----> Mg(OH)₂ + 2 KCL

One can note that 2 mol of KOH react with MgCl₂ to produce 1 mol of Mg(OH)₂.

using cross multiplication

2 mol of KOH → 1 mol of Mg(OH)₂.

4 mol of KOH → ?? mol of Mg(OH)₂.

no of moles of Mg(OH)₂ = (1 mol* 4 mol) / 2 mol =2 mol

Now we can convert moles of Mg(OH)₂ to grams using the formula

mass of Mg(OH)₂= (no. of moles * molar mass) = (2 mol * 58.3g/mol) = 116.6 g

• So, 4 mol of KOH would produce 116.6 g of Mg(OH)₂.