Question

The solution set for the equation x2 - 6x + 10 = 0 is

Answer 1

`\displaystyle\\x^2 - 6x + 10 = 0\\\\x_(12)=(-b\pm√(b^2-4ac))/(2a)=(6\pm√(36-40))/(2)=(6\pm√(-4))/(2)=(6\pm2i)/(2)=3\pm~i\\\\ \boxed{\bf~x_1=3-i}\\\boxed{\bf~x_2=3+i}`