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A drunk guy walking on a narrow lane takes 8 steps forward and 6 steps backward and so on.

Each step is 1m long and he requires 1 second to travel. The time that the drunk guy takes to fall in a pit 18m away from the starting point is


a) 18s
b) 126s
c) 78s
d) 62s

User Supercobra
by
5.9k points

1 Answer

1 vote

Answer: 126 secs

Explanation: he gains 2 steps every time and it takes 9 2 steps to reach 18 meters so what u do is take that 9 and multiply it to 14 (8+6) giving u ur answer of 126 secs.

User Chase
by
5.7k points