Question

A drunk guy walking on a narrow lane takes 8 steps forward and 6 steps backward and so on.

Each step is 1m long and he requires 1 second to travel. The time that the drunk guy takes to fall in a pit 18m away from the starting point is


a) 18s
b) 126s
c) 78s
d) 62s

Answer 1

Answer: 126 secs

Explanation: he gains 2 steps every time and it takes 9 2 steps to reach 18 meters so what u do is take that 9 and multiply it to 14 (8+6) giving u ur answer of 126 secs.