Question

Which function has real zeros at x=-8 and x=5?​

Answer 1

The answer is A

Explanation:

Answer 2

Answer: The required function would be
`x^2+3x-40`

Explanation:

Since we have given that

There are two real zeroes :

x = -8 and x = 5

So, we need to find the function satisfying the above two zeroes:

Let α = -8 and β = 5

So, it means it is a quadratic equation :

`x^2-(\alpha +\beta)x+\alpha \beta \\\\=x^2-(-8+5)x+-8* 5\\\\=x^2+3x-40`

Hence, the required function would be
`x^2+3x-40`