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The French club is sponsoring a bake sale. If their goal is to raise at least $135, how many pastries must they sell at $3.00 each in order to meet that goal? Write and solve an inequality.

135p ≥ 3.00; p ≥ 45


3.00p ≥ 135; p ≥ 405


3.00p ≥ 135; p ≥ 45


3.00p ≥ 135; p ≥ 132

2 Answers

3 votes

Answer:
3p\geq135 ;
p\geq45

Explanation:

Given : The French club is sponsoring a bake sale. If their goal is to raise at least $135 (greater than of equal to $135).

Let p be the number of pastries they sell.

If they sell at $3.00 each in order to meet that goal, then the total price of p pastries will be : 3p

Then, the inequality for the given statement will become:-


3p\geq135

Divide both sides by 3 , we get


p\geq45

Hence, they must sell 45 or more pastries to raise at least $135.

User Zhangxaochen
by
6.1k points
5 votes

Answer:

3.00p ≥ 135; p ≥ 45

Explanation:

You sell each for $3 so 3(pastries sold or p).

You want to make AT LEAST 135 (you could make more but not less.)

so 3.00p ≥ 135.

To solve: divide 135 by 3.

p ≥ 45

User Geoff Dawdy
by
6.1k points