Question

5. The load across a battery consists of two resistors, with values of 15 Ohm and 45 Ohm connected in series.

a) What is the total resistance of the load?

b) What is the voltage of the battery if the current in the circuit is 0.1 A?

Answer 1

a)
`60 \Omega`

The total resistance of resistors connected in series is equal to the sum of the individual resistances:

`R=R_1 + R_2 + .... + R_n`

In this problem, we have two resistors connected in series:

`R_1 = 15 \Omega`

`R_2 = 45 \Omega`

So the total resistance of the circuit is

`R=R_1 + R_2 = 15 \Omega + 45 \Omega = 60 \Omega`

b) 6.0 V

The relationship between voltage, current and resistance of a circuit is given by Ohm's law

`V=RI`

where

V is the voltage

R is the total resistance

I is the current

In this circuit, we have

`R=60 \Omega` is the total resistance

I = 0.1 A is the current

So, the voltage of the battery is

`V=(60 \Omega)(0.1 A)=6.0 V`