Answer:
![a_n=3(3)^(n-1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ao6h37bd6yuv1xrn4r0s9uoeguhkcddemj.png)
Explanation:
We have the following sequence
3,9,27,81,243
Note that if you divide each term of the sequence between the previous term you get:
![(9)/(3) = 3\\\\(27)/(9) = 3\\\\(81)/(27) = 3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8f03fju7utb7s0s7cq8q5xcd4pdv84jvjg.png)
then the radius of convergence of the series is r.
therefore this is a geometrical series.
The formula to find the general term
of the geometric sequence is:
![a_n=a_1(r)^(n-1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6v3rfhe5z7jrml57fnstj1iac4v6g2j3cw.png)
Where
is the first term of the sequence
Then the general term for this sequence is:
![a_n=3(3)^(n-1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ao6h37bd6yuv1xrn4r0s9uoeguhkcddemj.png)