232k views
3 votes
Given: DR tangent to Circle O.

Ir DB=140, then A=

A)70
B)110
C)140
D)80

The quiz says 140 is wrong, but I don’t know if that’s a problem on the teacher’s end or not, because everyone here says it’s 140

Given: DR tangent to Circle O. Ir DB=140, then A= A)70 B)110 C)140 D)80 The quiz says-example-1
User Yjshen
by
6.6k points

2 Answers

3 votes

Answer:

I believe the answer is 110.

User Remram
by
6.8k points
5 votes

Answer:

110°

Explanation:

In this problem we need to use the Inscribed Angle theorem, which states that an inscribed angle is one-half its subtended arc.


\angle C=(1)/(2)arc(DB)=70\°

Then, we use the theorem about a cyclic quadrilateral, which is an inscribed quadrilateral: "the opposite angles in a cyclic quadrilateral are supplementary".


\angle C + \angle A = 180\°\\\angle A = 180\° - \angle C\\\angle A = 180\° - 70\° \\\angle A = 110\°

Therefore, the answer is 110°

User Erjot
by
6.5k points
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