Question

suppose that 10 is less than square rooot of n which is less than 11 what is the possible value for n

Answer 1

The correct answer is that a possible value for n could be all numbers from 101 to 120.

Explanation:

Ok, to solve this problem:

You have that:
`10 <√(n) <11`

Then, applying the properties of inequations, the power is raised by 2 on both sides of the inequation:

`(10)^(2) <(√(n) )^(2) <(11)^(2)`

`100<n<121`

Then, a possible value for n could be all numbers from 101 to 120.