Answer:
The direction of the given vector is 45° N of W
Explanation:
* Lets revise the four directions with the four quadrants
- The four directions are:
# North which represented by the positive part of y-axis
# South which represented by the negative part of y-axis
# East which represented by the positive part of x-axis
# West which represented by the negative part of y-axis
∴ The first quadrant is between the East and the North
∴ The second quadrant is between the West and the North
∴ The third quadrant is between the West and the South
∴ The fourth quadrant is between the East and the South
* The direction of any vector is tan Ф, where Ф is the angle between
the vector and the x-axis, then:
- The direction of North of East is 45° ⇒ first quadrant
- The direction of North of West is 45° ⇒ second quadrant
- The direction of South of West is 45° ⇒ third quadrant
- The direction of South of East is 45° ⇒ fourth quadrant
* Now lets solve the problem
∵ The direction of the vector is between the North and the West
(its vertex in the second quadrant)
∴ Its direction is 45° North of West
* The direction of the given vector is 45° N of W