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Determine the number of real solutions of -2x^2+5x-3=0

User HappyPy
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1 Answer

4 votes

Answer:

Two distinct real solutions.

Explanation:

Given the equation in the form
ax^2+bx+c=0, you need to find the Discriminant with this formula:


D=b^2-4ac

For the equation
-2x^2+5x-3=0 you can identify that:


a=-2\\b=5\\c=-3

Then, substituting these values into the formula, you get that the Discriminant is:


D=5^2-4(-2)(-3)


D=1

Since
D>0, then
-2x^2+5x-3=0 has two distinct real solutions.

User Uiroshan
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