Question

Determine the number of real solutions of -2x^2+5x-3=0

Answer 1

Two distinct real solutions.

Explanation:

Given the equation in the form
`ax^2+bx+c=0`, you need to find the Discriminant with this formula:

`D=b^2-4ac`

For the equation
`-2x^2+5x-3=0` you can identify that:

`a=-2\\b=5\\c=-3`

Then, substituting these values into the formula, you get that the Discriminant is:

`D=5^2-4(-2)(-3)`

`D=1`

Since
`D>0`, then
`-2x^2+5x-3=0` has two distinct real solutions.