Question

Which system of linear inequalities has the point (3,-2) in its solution set?

A.y < -3
y ≤ 2/3x - 4
B.y > -3
y ≥ 2/3x - 4
C.y < -3
y ≥ 2/3x - 4
D.y > -2
y ≤ 2/3x - 4

(the answers come with graphs but sorry I couldn't find a way to put them all in)​

Answer 1

i think it is b as well! on edg

Explanation:

Answer 2

Option B.

Step-by-step explanation:

we know that

If a ordered pair is a solution of the system of inequalities

then

the ordered pair must satisfy both inequalities of the system

Verify each case

Case A) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

`-2< -3` ----> is not true

therefore

The ordered pair is not a solution of the system A

Case B) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

`-2> -3` ----> is true

Inequality 2

`-2 \geq (2)/(3) (3)-4`

`-2\geq -2` ----> is true

therefore

The ordered pair is a solution of the system B

Case C) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

`-2<-3` ----> is not true

therefore

The ordered pair is not a solution of the system C

Case D) we have

The point (3,-2)

Substitute the value of x and the value of y in both inequalities and then compare the results

Inequality 1

`-2>-2` ----> is not true

therefore

The ordered pair is not a solution of the system D