Question

A plane passes over point a with a velocity of 5000 m/s north. Sixty seconds later it passes over point b at a velocity of 10,000 m/s north. What is the plane’s acceleration from A to B?

Answer 1

The plane’s acceleration from A to B is

`a =83.33\ m/s^2`

Step-by-step explanation:

The acceleration of an object is a measure of how its speed changes over time.

In this case, we know that the plane initially has a velocity of 5000 m/s when it passes through point A, and when it passes through point B, 60 seconds later it has a velocity of 10,000 m/s.

Then the average acceleration is calculated as

`a =(s_2-s_1)/(t_2-t_1)`

Where

`s_2 = 10 000` is the final speed

`s_1=5000` is the initial velocity

`t_2 -t_1=60` is the time it took for the object to reach the final speed

Then

`a =(10000-5000)/(60)`

`a =(5000)/(60)`

`a =83.33\ m/s^2`