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1 vote
Find the slope of the straight line that passes through (–2, –4) and (3, –5)

2 Answers

4 votes

Hello there!

The slope is -1/5.

To find the slope, subtract the y values over the x values.

- 5 - - 4 / 3 - - 2 - Since subtracting a negative is the same as adding a positive, you can rewrite the equation like this: - 5 + 4 / 3 + 2.

You are left with -1/5, this cannot be simplified so this is your final answer. I hope this helps and have a great day! :)

User Axis
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6.1k points
5 votes

For this case we have that by definition, the slope of a line is given by:
m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

Only two points are needed through which the line passes.

Where:


(x_ {1}, y_ {1}): (- 2, -4)\\(x_ {2}, y_ {2}) :( 3, -5)

Substituting:


m = \frac {-5 - (- 4)} {3 - (- 2)}\\m = \frac {-5 + 4} {3 + 2}\\m = \frac {-1} {5}\\m = - \frac {1} {5}

Answer:


m=-(1)/(5)

User Tommyvn
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6.1k points