Question

How much heat energy is added to 2 grams of water if the initial temperature was 40°C and the final temperature is 50°C? (The specific heat of water is 4.18 J/g°C).

Answer 1

To calculate the amount of heat energy added to the water, multiply the mass of water by the specific heat of water and the change in temperature.

Step-by-step explanation:

To calculate the amount of heat energy added to the water, we can use the equation:

q = m * c * ΔT

Where q is the heat energy, m is the mass of the water (2 grams), c is the specific heat of water (4.184 J/g °C), and ΔT is the change in temperature (final temperature minus initial temperature).

Substituting the values into the equation, we get:

q = 2g * 4.184 J/g°C * (50°C - 40°C)

q = 2g * 4.184 J/g°C * 10°C

q = 83.68 J

Therefore, 83.68 Joules of heat energy is added to 2 grams of water.

Answer 2

10.5 kJ

Explanation:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c= 4.18 J g∘ C

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.