Answer:
![160 kg/m^3](https://img.qammunity.org/2020/formulas/physics/high-school/3p4ttltgoio4bxk8o1fhuh80atwytocib5.png)
Step-by-step explanation:
The density of the liquid is given by:
![d=(m)/(V)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3l3gbpcws9mzjhpmgj6k3k19i1df5avbro.png)
where
m is the mass of the liquid
V is its volume
The mass of the liquid is
m = 1.0 kg
while the volume is the volume of a cylinder with height h=0.20 m and radius r=0.10 m:
![V=\pi r^2 h = \pi (0.10 m)^2 (0.20 m)=6.28\cdot 10^(-3) m^3](https://img.qammunity.org/2020/formulas/physics/high-school/zux5xc2v1ke54zcg65sabaplg8mfd1btgd.png)
So, the density is
![d=(1.0 kg)/(6.28\cdot 10^(-3) m^3)=159.2 kg/m^3 \sim 160 kg/m^3](https://img.qammunity.org/2020/formulas/physics/high-school/e4ewxr0oai6mgfbg8k7556njqe75bdsm6u.png)